Correct Answer - Option 2 : 2xy
Given:
The terms are 4x2y, 16xy3, 2x3y3
Calculation:
Factors of 4x2y = 2 × 2 × x × x × y
Factors of 16xy3 = 2 × 2 × 2 × 2 × x × y × y × y
Factors of 2x3y3 = 2 × x × x × x × y × y × y
Common factors = 2 × x × y = 2xy
∴ HCF is 2xy