Correct Answer - Option 2 :
Only II
Given:
Average weight of n employees = 70 kg
Average weight of 10 employees who leave = 73 kg
Average weight of 5 employees who join = 70 kg
Difference in average weight = 0.4 kg
Formula Used:
Average = Sum of values/Number of values
Calculation:
Sum of the weight of 10 employees who leave/10 = 73 kg
⇒ Sum of the weight of 10 employees who leave = 730 kg
Sum of the weight of 5 employees who join/5 = 70 kg
⇒ Sum of the weight of 5 employees who join = 350 kg
Sum of the weight of n employees/n = 70 kg
⇒ Sum of the weight of n employees = 70n kg
∵ 10 employees leave and 5 join
∴ Number of employees left = n – 5
Sum of the weight of n – 5 employees/(n – 5) = 70 – 0.4
⇒ Sum of the weight of n – 5 employees = 69.6(n – 5)
⇒ 70n – 730 + 350 = 69.6n – 348
⇒ 0.4n = 32
⇒ n = 80 kg
I. 73 employees are left
80 – 10 + 5 = 75
⇒ I is not correct
II. n is a multiple of 16
80 = 5 × 16
⇒ II is correct
III. 70 < n < 80
⇒ 70 < n = 80
⇒ III is not correct
∴ Only II is correct