Correct Answer - Option 1 :
\(-1\over3\)
Calculation:
Given tan A = √3 sin A
\(\rm \sin A\over\cos A\) = √3 sin A
cos A = \(1\over\sqrt3\)
cos2 A = \(1\over3\)
∵ cos2 A + sin2 A = 1
1 - sin2 A = \(1\over3\)
1 - \(1\over3\) = sin2 A
sin2 A = \(2\over3\)
Now cos2 A - sin2 A = \(1\over3\) - \(2\over3\)
cos2 A - sin2 A = \(-1\over3\)