Correct Answer - Option 3 : 10
-2
Data:
Period = T = 100 ms
Formula:
\({\rm{Frequency\;f}} = \frac{1}{{\rm{T}}}{\rm{\;}}\)
Calculation:
\({\rm{f}} = \frac{1}{{100{\rm{\;ms}}}} = \frac{1}{{100 × {{10}^{ - 3}}{\rm{s}}}} = 10{\rm{\;}}{{\rm{s}}^{ - 1}} = 10{\rm{\;Hertz}}\)
f = 10 × 10-3 kilohertz = 10-2 kilohertz
