Question

Sajal travels from A to B at a speed of 50 km/h and from B to C at a speed of 100 km/h. Find the distance covered in 3 hours with his average speed if the distance from B to C is twice the distance from A to B. 
1. 150 km
2. 180 km 
3. 225 km 
4. 250 km

Answer 1

Correct Answer - Option 3 : 225 km 

Given :

Sajal travel from A to B at a speed of 50 km/h

B to C at a speed of 100 km/h

Distance of B to C = 2 × Distance of A to B

Formula used :

Average speed = Total distance/Total time

Calculations :

Let the distance from A to B is 'x' km 

Let the distance from B to C be '2x' km

Total time = (x/50) + (2x/100)

⇒ x/25 hours 

Average speed = 3x/(x/25)

⇒ 75 km/h 

Now distance covered in 3 hours with this average speed 

Distance = 75 × 3   

⇒ 225 km 

∴ The total distance covered will be 225 km.