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Find the least number when divided by 10, 14 and 42 leaves remainder 9 in each case but completely divisible by 13
1. 219
2. 429
3. 349
4. 169

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Correct Answer - Option 2 : 429

Concept 

LCM: The Least common multiple or lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

Calculation

The Least number divisible by 10, 14 and 42 = LCM(10, 14, 42)

10 = 2 × 5 

14 = 2 × 7

42 = 2 × 3 × 7

⇒ LCM(10, 114, 42) = 210

The least number divisible by 10, 14 and 42 which leaves remainder 9 in each case = (210 × p) + 9, where 'p' is a natural number 

⇒ (210 × p) + 9 is completely divisible by 13

Putting values of p = 1, 2, 3... etc we get,

For p = 1

(210 × p) + 9 = 210(1) + 9 = 219, which is not divisible by 13

For p = 2

(210 × p) + 9 = 210(2) + 9 = 429, which is divisible by 13

∴ The least number  which when divided by 10, 14 and 42 leaves remainder 9 in each case but completely divisible by 13 is 429.

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