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If two-third work is completed by G in 17 days and H is twice as efficient as G, find the time taken by H in completing full piece of work.


1. 13 days
2. 14.7 days
3. 12.75 days
4. 15.5 days

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Correct Answer - Option 3 : 12.75 days

Given:

Two-third work is completed by G in 17 days.

H is twice as efficient as G.

Concepts used:

Time = Work/Efficiency

1 day work of individual = Work/Time

Calculation:

Two-third work is completed by G in 17 days.

⇒ Efficiency of G = Work/Time

⇒ Efficiency of G = (2/3)/17 = 2/51

H is twice as efficient as G.

⇒ Efficiency of H = 2 × 2/51 = 4/51

Time = Work/Efficiency

⇒ Time taken by H to complete full piece of work = 1/(4/51) days = 51/4 days = 12.75 days

H completes full piece of work in 12.75 days.

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