Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
60 views
in Calculus by (113k points)
closed by
\(\rm \int_{ - 5}^{\ \ 5} \left| {x + 2} \right|dx\) is equal to:
1. 28
2. 30
3. 29
4. 27
5. 25

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 3 : 29

Concept:

The Modulus Function '| |' is defined as: \(\rm |x|=\left\{\begin{matrix}\rm \ \ \ x, &\rm x \geq 0\\ \rm -x, &\rm x<0\\\end{matrix}\right.\).

 

Calculation:

Consider |x + 2|.

|x + 2| = x + 2 for x ≥ -2.

|x + 2| = - x - 2 for x < -2.

Now, \(\rm \int_{ - 5}^{\ \ 5} \left| {x + 2} \right|dx\):

\(\rm \int_{ - 5}^{-2} (-x-2)\ dx+\int_{-2}^{\ \ 5} (x+2)\ dx\)

\(\rm \left[\frac{-x^2}{2}-2x\right]_{ - 5}^{-2}+\left[\frac{x^2}{2}+2x\right]_{-2}^{\ \ \ 5}\)

\(\rm \left(\frac{-4}{2}+4\right)-\left(\frac{-25}{2}+10\right)+\left(\frac{25}{2}+10\right)-\left(\frac{4}{2}-4\right)\)

= 29.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...