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There are 10 points in a plane of which 4 are collinear. Find the number of triangles that can be formed with vertices at these points.


1. 210
2. 116
3. 120
4. 24

1 Answer

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Best answer
Correct Answer - Option 2 : 116

Concept:

The number of ways to select r things out of n things is given by \(\rm ^nC_r\)

\(\rm ^nC_r=\frac{n!}{(n-r)!\times(r)!}=\frac{n\times(n-1)\times....(n-r+1)}{r!}\)

 

Calculation:

To form a triangle we have to select 3 points out of 10 points,  

∴Number of triangles that can be formed from 10 points = \(\rm ^{10}C_3=\frac{10\times9\times8}{3\times2\times1}\)

= 120

Also, the number of triangles that can be formed from 4 points = \(\rm ^4C_3=\frac{4\times3\times2}{3\times2\times1}\)

= 4

But, these 4 points are collinear and it is not possible to form a triangle out of these points.

∴ Number of triangles that can be formed with 10 points in a plane of which 4 are collinear

= 120 - 4

= 116

Hence, option (2) is correct. 

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