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Equation of line passes through point (2, 5) and perpendicular to the line 2y = 4x +3
1. -x + 2y=12
2. x + 2y = 12
3. 2x + y = 5
4. 2y -x = 10

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Correct Answer - Option 2 : x + 2y = 12

Concept: 

y = mx + b, is the equation of the line, where m = slope of the line and b = y-intercept of the line.

  • If two lines are parallel, then their slopes are equal, m1= m2.
  • If two lines are perpendicular to each other then the product of there slopes is equal to -1, m1m2= -1. 

Equation of line passing through point (x1, y1) and whose slope is m , (y - y1) = m (x - x1).  

Calculation: 

Equation of given line is ,  2y = 4x +3 

∴ y = 2x + \(\frac{3}{2}\) 

On comparing with standard equation ,  y = mx + c,  slope of line is 2 .

As we know that , if lines are perpendicular to each other  ,  m1m2= -1.   

Then slope of line passes through point (2,5) and perpendicular to the given line is \(\frac{1}{2}\)  

∴ Equation of line is , (y - 5) = - \(\frac{1}{2}\) (x - 2) 

⇒ 2y -10 = -x + 2 

⇒ x + 2y = 12 . 

The correct option is 2.

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