Correct Answer - Option 2 : 0
Given:
x = (29 × 37 × 42 × 65 × 73 × 57)/45
Calculations:
x = (29 × 37 × 42 × 65 × 73 × 57)/(32 × 5)
⇒ x = (29 × 37 × (3 × 16) × (5 × 13) × 73 × (3 × 19))/(32 × 5)
We observe x is multiple of 32 and 5 both
⇒ x is divisible by 45
⇒ Remainder = 0
∴ The remainder when x is divided by 45 is 0.