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Two buses travel at speeds 47 km/h and 42 km/h from two cities a certain distance apart, towards each other. At the time of their meeting, the faster bus has traveled 55 km more than the slower bus. Find the distance between the two cities. 
1. 979 km
2. 1035 km
3. 923 km
4. 954 km

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Best answer
Correct Answer - Option 1 : 979 km

Given:

Speeds = 47 km/h and 42 km/h

Difference in distance traveled = 55 km

Formula used:

Speed = distance/time

Calculation:

Let the buses meet after 't' hours

A.T.Q

47t - 42t = 55

⇒ 5t = 55

⇒ t = 11

Total distance = (47 + 42) × 11 = 979 km

∴ The distance is 979 km

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