Correct Answer  Option 1 : 10 m/s
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CONCEPT:

Velocity: The displacement per unit time is called velocity.
\(v = {Δ x \over Δ t}\)
where v is the velocity, Δx is the change in displacement, Δt is the change in time.

Acceleration (a): The rate of change of velocity is known as acceleration.
\(\overrightarrow{a} = {\overrightarrow{Δ v} \over Δ t} \)
where a is the vector quantity, Δv is the velocity, and Δt is the time.
CALCULATION:
Given that position of a particle is given by: x = 5t2 + 2t + 5
velocity \(v = {Δ x \over Δ t}\)
\(v = {d x \over d t}={d \over d t}(5t^2 + 2t + 5) = 10t+2\)
\(\overrightarrow{a} = {\overrightarrow{Δ v} \over Δ t} = {d(10t+2) \over d t} =10 m/s^2\)
So the correct answer is option 1.