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How many zeroes will be there at the end of 1253 × 2100 + 731 × 212 × 510 + 611 × 5 × 730?
1. 9
2. 12
3. 1
4. 0

1 Answer

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Best answer
Correct Answer - Option 3 : 1

Given:

1253 × 2100 + 731 × 212 × 510 + 611 × 5 × 730

Concept Used:

Number of zeros = Number of pairs of 2 × 5

Calculation:

1253 × 2100 + 731 × 212 × 510 + 611 × 5 × 730

⇒ 59 × 2100 + 731 × 212 × 510 + 211 × 311 × 5 × 730

⇒ 5 × 2(58 × 299 + 731 × 211 × 59 + 210 × 311 × 730)

⇒ 10(58 × 299 + 731 × 211 × 59 + 210 × 311 × 730)

The number of zeros is 1.

Short Trick:

The number of zeros in any such expression will depend on the least zero holder term in the expression. In the given expression 3rd term contributes the least number of zeros as it contains only one power of 5.

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