Correct Answer - Option 1 : 75% more

**Given:**

Percentage of marks scored by Ritu more than Saket = 40%

Percentage of marks scored by Saket more than Aditya = 25%

**Concept Used:**

If a is x% more than b then,

a = (100 + x)% × b

**Calculations:**

Let the marks of Ritu, Saket and Aditya be a, b and c respectively.

Percentage of marks scored by Ritu more than Saket = 40%

⇒ a = (100 + 40)% × b = (140/100)b = (7/5)b

⇒ a : b = 7 : 5 ----(1)

Percentage of marks scored by Saket more than Aditya = 25%

⇒ b = (100 + 25)% × c = (125/100)c = (5/4)c

⇒ b : c = 5 : 4 ----(2)

From (1) and (2), we get

a : b : c = 7 : 5 : 4

Percentage of Ritu's marks more than Aditya's = (7 - 4)/4 × 100

⇒ Percentage of Ritu's marks more than Aditya's = (3/4) × 100 = 75%

**∴ The percentage of Ritu's marks more than Aditya's marks is 75%.**