Correct Answer - Option 1 : 75% more
Given:
Percentage of marks scored by Ritu more than Saket = 40%
Percentage of marks scored by Saket more than Aditya = 25%
Concept Used:
If a is x% more than b then,
a = (100 + x)% × b
Calculations:
Let the marks of Ritu, Saket and Aditya be a, b and c respectively.
Percentage of marks scored by Ritu more than Saket = 40%
⇒ a = (100 + 40)% × b = (140/100)b = (7/5)b
⇒ a : b = 7 : 5 ----(1)
Percentage of marks scored by Saket more than Aditya = 25%
⇒ b = (100 + 25)% × c = (125/100)c = (5/4)c
⇒ b : c = 5 : 4 ----(2)
From (1) and (2), we get
a : b : c = 7 : 5 : 4
Percentage of Ritu's marks more than Aditya's = (7 - 4)/4 × 100
⇒ Percentage of Ritu's marks more than Aditya's = (3/4) × 100 = 75%
∴ The percentage of Ritu's marks more than Aditya's marks is 75%.