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The interval in which the function f(x) = 2x3 - 15x2 + 36x + 12 is increasing in
1. (-∞, 2] ∪ (3, ∞)
2. (-∞, 2) ∪ (3, ∞)
3. (-∞, 2] ∪ [3, ∞)
4. (-∞, 2) ∪ [3, ∞)
5. None of these

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Correct Answer - Option 3 : (-∞, 2] ∪ [3, ∞)

Concept:

If f′(x) ≥ 0 at each point in an interval, then the function is said to be increasing.

Calculations:

We know that, If f′(x) ≥ 0 at each point in an interval I, then the function is said to be increasing on I. 

Given , f(x) = 2x3 - 15x2 + 36x + 12

Differentiating, we get

f'(x) = 6x2 - 30x + 36

f(x) is increasing function

⇒ f'(x) ≥ 0

⇒ 6x2 - 30x + 36 ≥ 0

⇒ x2 - 5x + 6 ≥ 0

⇒ (x - 2)(x - 3) ≥ 0

Hence, x ∈ (-∞, 2] ∪ [3, ∞)  

The interval in which the function f(x) = 2x3 - 15x2 + 36x + 12 is increasing in  (-∞, 2] ∪ [3, ∞)

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