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Average earning of each member of A's family is 50% less than the average earning of each member of B's family. The total earning of A's family is 33.33% more than that of B's family. The number of person of B's family is what percent of the number of person of A's family ?
1. 40%
2. 37.5%
3. 62.5%
4. 50%

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Correct Answer - Option 2 : 37.5%

Given:

Average earning of each member of A's family is 50% less than the average earning of each member of B's family. The total earning of A's family is 33.33% more than that of B's family.

Concept used:

Percentage

Calculation:

Let the number of members in A's family be x and in B's family be y

Ratio of average earning of A and B

⇒ A : B = 1 : 2

Total earning ratio of A and B 

⇒ A : B = x : 2y

As per the question,

The total earning of A's family is 33.33% more than that of B's family

⇒ \(\frac{x}{{2y}} = \frac{4}{3}\)

⇒ \(\frac{x}{y} = \frac{8}{3}\)

To find, The number of person of B's family is what percent of the number of person of A's family

⇒ \( \frac{y}{x} \times 100\)

⇒ \(\frac{3}{8} \times 100 = 37.5\% \)

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