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Find 7th term of the arithmetic progression series in which 2nd and 5th terms are 7 and 13 repectively.
1. 17
2. 13
3. 19
4. 21

1 Answer

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Correct Answer - Option 1 : 17

Concept:

The nth number in A.P. series = Tn = a + (n - 1)d

Where 'a' is the first number of the series and 'd' is the common difference

Calculation:

Let the first element of A.P. is 'a' and the common difference is 'd'

Given:

2nd and 5th terms in the arithmetic progression are 7 and 13 respectively.

The second term = 7

⇒ a + d = 7           ----(i)

And the fifth term = 13

⇒ a + 4d = 13      ----(ii)

After subtracting equation (ii) from equation(i) we get,

⇒ 4d - d = 13 - 7

⇒ 3d = 6

⇒ d = 2

Put the value of d in equation (1), we get

⇒ a + 2 = 7

⇒ a = 7 - 2

⇒ a = 5

Now 7th term = a + 6d

= 5 + 6 × 2

= 5 + 12

= 17

∴ The 7th term in arithmetic series is 17  

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