Correct Answer - Option 1 : 81 RPM
Concept:
Specific speed of a centrifugal pump is given by:
\({N_s} = \frac{{N\sqrt Q }}{{H_m^{3/4}}}\)
Calculation:
Given:
Q = 810 l/s = 0.81 m3/s, H = 16 m, N = 725 RPM
\({N_s} = \frac{{N\sqrt Q }}{{H_m^{3/4}}}\) = \(\frac{{725\sqrt{0.81}}}{{16^{3/4}}}\) = 81.56 RPM
Option a is closed to the answer.
