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Equation of a line having slope 2 and the point (1, 2) lies on the line 
1. 3y - x - 3 = 0
2. y - 2x = 0
3. y + 3x - 11 = 0
4. 3y + x - 9 = 0

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Correct Answer - Option 2 : y - 2x = 0

Concept:

The general equation of a line is y = mx + c 

where m is the slope and c is any constant

  • Slope of parallel lines is equal.
  • Slope of the perpendicular line have their product = -1

Equation of a line with slope m and passing through (x1, y1)

(y - y1) = m (x - x1)

Equation of a line passing through (x1, y1) and (x2, y2) is:

\(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\)

Calculation:

Given the line has the slope 2 and passes through (1, 2)

∴ Equation of the line is

(y - y1) = m (x - x1)

⇒ y - 2 = 2 (x - 1)

⇒ y - 2 = 2x - 2

⇒ y - 2x = 0

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