Question

Find the roots of the quadratic equation:

6x² + 41 x + 63 = 0

1. 2,-1
2. 3/2, -7/5
3. -7/3, -9/2
4. -3, -7

Answer 1

Correct Answer - Option 3 : -7/3, -9/2

Given:

6x2 + 41 x + 63 = 0

Calculation:

Using middle term factorisation:

6x² + 14x + 27x + 63 = 0     ∵ (14 ×  27 = 6 × 63 = 378 & 14 + 27 = 41)

2x ( 3x + 7 ) + 9 ( 3x + 7 ) = 0

( 2x + 9 ) ( 3x + 7 ) = 0

So, the roots are:

2x + 9 = 0 

x = -9/2

3x + 7 = 0

x = -7/3

∴ The value of roots for the quadratic equation 6x2 + 41 x + 63 = 0 is -9/2 and -7/3