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In the simple harmonic motion, the velocity of a particle lags acceleration by ______.
1. 0° 
2. 90° 
3. 180° 
4. 270° 

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Correct Answer - Option 2 : 90° 

CONCEPT:

  • Simple harmonic motion: The motion in which the restoring force is directly proportional to the displacement from equilibrium is simple harmonic motion.

⇒ F α -x

Where F = force and x = the displacement from mean position equilibrium.

  • The equation of displacement in Simple Harmonic Motion is given by:

⇒ x = A sin(ωt + ϕ) .........(i)

where x is the distance from the mean position or equilibrium at any time t, A is amplitude (max displacement), ω is the angular frequency, and t is time.

  • The equation of velocity in Simple Harmonic Motion is given by differentiating equation (i)

\(⇒ v={dx \over dt} = {d (A sin(ωt + ϕ)) \over dt}\)

⇒ v = Aω cos(ωt + ϕ) ...........(ii)

where v is the velocity at any time t, A is amplitude (max displacement), ω is the angular frequency, and t is time.

  • The equation of acceleration in Simple Harmonic Motion is given by differentiating equation (ii)

\(⇒ a={dv \over dt} = {d (A\omega cos(ωt + ϕ)) \over dt}\)

⇒ a = -Aω2 sin(ωt + ϕ)​

where a is the acceleration at any time t, A is amplitude (max displacement), ω is the angular frequency, and t is time.

CALCULATION:

  • Equation of velocity

⇒ v = Aω cos(ωt + ϕ)

⇒ v = Aω sin(ωt + ϕ + π/2)

Phase of displacement = ωt + ϕ + π/2

  • Equation of acceleration is 

⇒ a = -Aω2 sin(ωt + ϕ)

⇒ a = Aω2 sin(ωt + ϕ + π)

Phase of acceleration = ωt + ϕ + π

  • Difference between phase of acceleration and phase of velocity

⇒ Δϕ =  (ωt + ϕ + π) - (ωt + ϕ + π/2) = π/2 or 90° 

  • So velocity lags acceleration by 90°. So the correct answer is option 2.

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