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ABC is an isosceles right angled triangle with ABC =90°. A semi -circle is drawn with AC

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ABC is an isosceles right angled triangle with ABC =90°. A semi -circle is drawn with AC as the diameter. If AB = BC =17 cm, find the area of the shaded region.(Take π =22/7) 

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∴ Area of shaded region  = (Area of semi circle) - Area of Δ ABC

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