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The copper cathod is increased in weight by 0.05 kg in two hours in a copper sulphate voltameter, when the current was maintained constant. Determine the value of his current. It is know that the atomic weight of copper = 63.5; atomic weight of Hydrogen = 1; atomic weight of silver: 108; Electro-chemical equivalent of silver = 111.8 × 10-8 kg / C.
1. 21.1 A
2. 28.7 A
3. 11.6 A
4. 50 A

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Correct Answer - Option 1 : 21.1 A

Concept:

Faraday’s Laws of Electrolysis:
Faraday deduced two fundamental laws which govern the phenomenon of electrolysis. These are :

First Law: The mass of ions liberated at an electrode is directly proportional to the quantity of electricity i.e. charge which passes through the electrolyte.

Second Law: The masses of ions of different substances liberated by the same quantity of electricity are proportional to their chemical equivalent weights.

Explanation of the Faradays Law:

If m = mass of the ions liberated,
Q = quantity of electricity = I × t
Where I is the current and t is the time

According to the first law:

m ∝  Q

or m = Z Q

or m = Z It

Where Z is a constant and is known as the electrochemical equivalent (E.C.E.) of the substance and it is given by,

\(Z=\frac{a}{Fv}\)

Where,

F is Faraday's constant and is defined as the charge required to liberate one gram-equivalent of any substance.

The value of F for all substance is given by,

\(F=\frac{E.C.E}{Z}=96500 \ C\)

a is the atomic weight
v is the valency

Calculation:

Given,

m = 0.05 kg = 50 g

t = 2 hours = 7200 s

a = 63.5 amu

valency of copper (v) = 2

From the above concept,

\(Z=\frac{a}{Fv}=\frac{63.5}{96500\times 2}=3.29\times 10^{-4}\)

We know that,

m = Z It

\(I=\frac{m}{Zt}=\frac{50}{3.29\times 10^{-4}\times 7200}=21.10\ A\)

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