Correct Answer - Option 3 : -4 cos 2x
Concept:
Second-order Derivative.
\(\rm \frac {d^2 f(x)}{dx^2} = \) \(\rm \frac {d}{dx} [\frac {d}{dx} f(x)]\)
\( \rm \frac {d}{dx} \cos x = -\sin x\)
\( \rm \frac {d}{dx} \sin x = \cos x\)
Calculations:
Given:
\(\rm \dfrac {d^2 \cos2x}{dx^2}\)
= \(\rm \dfrac {d}{dx} (\dfrac {d}{dx} cos2x)\)
= \(\rm \dfrac {d}{dx} (- 2sin2x)\)
= \(\rm -2\;\dfrac {d}{dx} ( sin2x)\)
= -2 × 2 cos 2x
= -4 cos 2x