Correct Answer - Option 3 : 2x + 4
Concept used:
If y = elogx then y = x
\(\rm d(x^n)\over{dx} \) = nxn - 1
Calculations:
Given, f(x) = e4log (x2 + 4x - 6)
So, f(x) = x2 + 4x - 6 (∵ elog x = x)
Taking derivative with respect to x on both side, we get
f'(x) = 2x + 4