Question

The area of trapezium having its parallel sides equal to x + 3 and 2x + 7 and its height 18 cm
is 144 cm². The difference of its parallel sides is:

1. 7 cm
2. 10 cm
3. 6 cm
4. 5 cm

Answer 1

Correct Answer - Option 3 : 6 cm

Given:

parallel sides =  x + 3 and 2x + 7

height 18 cm

The area of trapezium = 144 sq. cm

Concept used:

The area of trapezium = (1/2) × h × (sum of parallel sides)

Calculation:

sum of parallel sides = x + 3 + 2x + 7 = 3x + 10

144 = (18/2) × (3x + 10)

3x + 10 = 144/9 = 16

Then, x = 2

Difference between parallel sides = 2x + 7 - (x + 3) = (4 + 7) - (2 + 3) 

∴ The difference between parallel sides is 6 cm.