Correct Answer - Option 2 : 26.25 km
Given:
Arun and Barun walk from P to Q which are at a distance of 21 km.
The speed of Arun and Barun is 3kmph and 5 kmph respectively.
Barun reaches at Q and returns immediately and meets Arun at point T
Formula Used:
Time = Distance/ Speed
Calculation:
Let distance between P and T be ‘x’ km.
Thus, in time in which Arun covers x km, Barun covers 21 km + (21 – x) km
⇒ x/3 = [21 + (21 – x)] / 5
⇒ 5x = 3 [42 – x)]
⇒ 5x = 126 – 3x
⇒ 8x = 126
⇒ x = 126/8 = 15.75 km
Thus, Distance travelled by Braun when he meets Arun at point T = 21 km + (21 – x) km
= 21 + 5.25
= 26.25 km
