Correct Answer - Option 1 : 40/3 hours
Given
Pipe L can fill a tank without leakage in 8 hours
Pipe L can fill a can't with leakage in 20 hours.
Calculation
Let the leakage empty the tank in x hours.
Tank filled in 1 hour without leakage = (1/8)
Tank empty in 1 hour due to leakage = (1/x)
Tank filled in 1 hour with leakage = (1/20)
According to question
Tank filled in 1 hour with leakage = Tank filled in 1 hour without leakage - Tank empty in 1 hour with leakage
(1/20)= (1/8) - (1/x)
⇒ (1/x) = (1/8) - (1/20)
⇒ (1/x) = (5 - 2)/40
⇒ (1/x) = 3/40
⇒ x = 40/3
∴ Tank empty in 40/3 hours due to leakage.