Correct Answer - Option 2 : 27
Concept:
Load-Life relationship of a Bearing:
\({L_{10}} = {\left( {\frac{C}{P}} \right)^n}\)
L10 = Rated bearing life (in million revolutions), C = Dynamic load-carrying capacity, P = Load acting on the bearing
n = 3 for ball bearing and n = 10/3 for roller bearing.
Calculation:
Given:
PP = 15 kN, PQ = 45 kN, n = 3 (∵ ball bearing) and CP = CQ (∵ identical bearing).
\({L_{10}} = {\left( {\frac{C}{P}} \right)^n}\)
\(\therefore \frac{{{L_P}}}{{{L_Q}}} = {\left( {\frac{{{P_Q}}}{{{P_P}}}} \right)^3} = {\left( {\frac{{45}}{{15}}} \right)^3} = 3^3 =27 \)