Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
66 views
in Calculus by (115k points)
closed by
The value of \(\mathop \smallint \limits_0^{\frac{\pi }{2}} \frac{{\sin xdx}}{{\sin x + \cos x}}\)
1. 1
2. π/2
3. π/4
4. π/6

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 3 : π/4

Concept:-

By the properties of definite integral –

\(\mathop \smallint \limits_b^a f\left( x \right)dx = \frac{{upper\;limit - lower\;limit}}{2}\)

\(\mathop \smallint \limits_b^a f\left( x \right)dx = \frac{{a - b}}{2}\;\; - - - \left( 1 \right)\)

Calculation:

Given,

Using equation (1)

Given, \(\mathop \smallint \limits_0^{\pi /2} \frac{{\sin x}}{{\sin x + \cos x}}dx\)

Using equation (1)  \(\mathop \smallint \limits_0^{\pi /2} \frac{{\sin x}}{{\sin x + \cos x}}dx = \frac{{\frac{\pi }{2}\; - \;0}}{2}\)

\( = \frac{\pi }{4}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...