Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
746 views
in Physics by (115k points)
closed by
If kinetic energy is doubled, find fractional change in momentum
1. √2
2. 2√2
3. \(\frac{1}{\sqrt{2}}\)
4. \(\frac{1}{2}\sqrt2\)

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 1 : √2

Concept:

Momentum

  • Momentum is defined as the product of the mass and velocity of the body. 
  • It is a vector quantity directed toward velocity. 
  • It is given as 

p = mv      ----(1)

m is mass, v is the velocity, p is momentum

Kinetic Energy

  • The energy of a body in motion due to its state of motion is called kinetic energy. 
  • It is given as 


\(K = \frac{1}{2}mv^2\)        ----(2)

K is kinetic energy, m is mass, v is speed.

Relationship between Momentum and Kinetic Energy

If we combine equation (1) and (2) we will get the relationship between momentum and kinetic energy as

\(K = \frac{p^2}{2m}\)     ----(3)

Calculation:

If kinetic energy is doubled, then new Kinetic energy K' and new momentum is p'.

K' = 2 K

p' = ?

By the relationship of Kinetic energy and momentum, we can say that

\(K' = \frac{p'^2}{2m}\)

\(\Rightarrow 2K = \frac{p'^2}{2m}\) -- (4)

Putting (3) in (4)

\(\Rightarrow 2\frac{p^2}{2m} = \frac{p'^2}{2m}\)

⇒ 2 p = p'

⇒ p' = √2p

Fractional Change \(\frac{\Delta p}{p} = \frac{p' -p}{p}\)

\(\Rightarrow \frac{\Delta p}{p} = \frac{\sqrt 2 p -p}{p} = \sqrt2 -1\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...