Correct Answer - Option 1 : 0.467 m/s
Concept:
According to Lacey, the design formulas to build canal is as follows:
(1) Silt factor ⇒ \(\rm{f = 1.76\sqrt {{d_{mm}}}}\)
(2) Velocity of flow ⇒\(V = {\left[ {\frac{{Q{f^2}}}{{140}}} \right]^{\frac{1}{6}}}\)
(3) Hydraulic mean depth ⇒\(R = \frac{{5{V^2}}}{{2f}}\)
(4) Wetted perimeter ⇒ \(P = 4.75\sqrt Q\)
(5) Bed slope ⇒ \(S = \frac{{{f^{\frac{5}{3}}}}}{{3340 \times {Q^{\frac{1}{6}}}}}\)
Calculation:
Given,
Q = 2.01 m3/s, f = 0.85
∵ We know that, \(V = {\left[ {\frac{{Q{f^2}}}{{140}}} \right]^{\frac{1}{6}}}\)
\(V = {\left[ {\frac{{2.01 \times {{0.85}^2}}}{{140}}} \right]^{1/6}} = 0.467\ m/s\)