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Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is Rs.2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is
1. 36
2. 33
3. 30
4. 27

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Correct Answer - Option 2 : 33

Calculation:

Let Aron has x pencils

⇒ Aditya has 2x pencils

⇒ Cost of pencils be p

⇒ Cost of x pencils = xp

⇒ Cost of 2x pencils = 2xp

⇒ 2xp - xp = xp

⇒ Aron has y sharpner

⇒ Cost of y sharpners = y(p + 2)

⇒ Aditya has y - 10 sharpner

⇒ Cost of Aditya's sharpner = (y - 10)(p + 2)

⇒ y(p + 2) -(y - 10)(p + 2) = 10(p + 2)

According to questions

⇒ xp = 10(p + 2)

⇒ (x - 10)p = 20

⇒ Minimum value of x = 11

∴ Total pencils = 3x

∴ Minimum value of pencils bought by Aron and Aditya together is is  3 × 11 = 33

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