Correct Answer - Option 1 : 4000 kg/cm
2
Concept:
Bulk modulus (K) \( = \frac{{ - {\rm{\Delta }}P}}{{\left( {\frac{{{\rm{\Delta }}V}}{V}} \right)}}\)
Where, ΔV = change in volume = V2 – V1, ΔP = change in pressure = P2 – P1
Calculation:
Given:
V1 = 0.04 m3 = 40000 cm3, V2 = 0.039 m3 = 39000 cm3, P1 = 100 kg/cm2, P2 = 200 kg/cm2, K = ?
ΔV = V2 – V1 = 39000 - 40000 = -10000 cm3,
ΔP = P2 – P1 = 100 kg/cm2.
Bulk modulus (K) \( = \frac{{ - {\rm{\Delta }}P}}{{\left( {\frac{{{\rm{\Delta }}V}}{V}} \right)}}\)
K \(= \frac{{ - \left( {200 - 100} \right)}}{{\frac{{\left( {39000 - 40000} \right)}}{{40000}}}}\)
K = 4000 kg/cm2