Correct Answer - Option 3 : 20/3 days
Given:
A can complete the work in 10 days
B can complete the same work in 6 days
C can complete the same work in 5 days
Formula Used:
Work = Efficiency × Time
Calculation:
Let total work of A, B, C be a multiple of 10, 6, 5.
⇒ Total work = 60
Efficiency of A = 60/10
⇒ Efficiency of A = 6
Efficiency of B = 60/6
⇒ Efficiency of B = 10
Efficiency of C = 60/5
⇒ Efficiency of C = 12
Working alternatively means First day A works Second day B works and third day C works and this will continue till the completion of the work
⇒ Cycle of A, B, C repeats in every 3 days
In three days they will complete = 6 + 10 + 12
⇒ 28
In 6 days they will complete = 2 × 28
⇒ 56
Work left after 6 days = 60 – 56
⇒ 4
Now, it is A's turn, time taken by A = 4/6
⇒ 2/3 days
Total time is taken to complete the work = 6 + 2/3
∴ The total time is taken to complete the work is 20/3 days
Alternatively means one person will work on a day and in the sequence.
∴ The work will be completed in 20/3 days.
