Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
70 views
in Aptitude by (114k points)
closed by
The sides of similar triangles ΔMNO and ΔDEF are in the ratio 4 ∶ 7. If area of ΔMNO is equal to 128 cm2, what is the area of ΔDEF? 
1. 400 cm2
2. 392 cm2
3. 360 cm2
4. 358 cm2

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 2 : 392 cm2

Given:

ΔMNO ∼ ΔDEF

The sides of ΔMNO and ΔDEF are in the ratio 4 ∶ 7.

Area of (ΔMNO) = 128 cm2

Concepts used:

The ratio of the area of similar triangles is equal to the square of the ratio of sides of corresponding triangles.

Calculation:

ΔMNO ∼ ΔDEF

Area (ΔMNO)/Area (ΔDEF) = (Side of ΔMNO/Side of ΔDEF)2

⇒ 128 cm2/Area (ΔDEF) = (4/7)2

⇒ Area (ΔDEF) = 128 × (49/16) cm2

⇒ Area(ΔDEF) = 392 cm2.

∴ Area of ΔDEF is equal to 392 cm2.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...