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Comprehension

Direction: Study the given data carefully and answer the following question.

There are 3 cars A, B and C. They can travel some distance with different speed.

Car A: It travels some distance which is \(33\frac{1}{3}\% \) more than the distance travelled by Car B.

Car B: It travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.

Car C: It goes a distance of 400 km at 20% less speed than Car B.


1. 7 hours
2. 9 hours
3. 5 hours
4. 8 hours
5. 10 hours

1 Answer

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Correct Answer - Option 4 : 8 hours

Given:

Car A travels some distance which \(33\frac{1}{3}\% \) more than the distance travelled by Car B.

Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.

Car C travels a distance of 400 km at 20% less speed than Car B.

The Car A takes 8 hours to travel the distance.

Concept Used:

Distance = Speed × Time 

Calculation:

Car C speed is 20% less than Car B.

The speed of Car C = (100 - 20)/100 × 50 = 40 km/hr

Car B travels at speed of 50 km/hr.

The distance travels by Car C in 2 hours = 40 × 2 = 80km 

The relative velocity of Car B and Car C = 50 - 40 = 10 km/hr

The time when Car B meets Car C = 80/10 = 8 hours

∴ Car B meets Car C after 8 hours.

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