Correct Answer - Option 4 : 8 hours
Given:
Car A travels some distance which \(33\frac{1}{3}\% \) more than the distance travelled by Car B.
Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.
Car C travels a distance of 400 km at 20% less speed than Car B.
The Car A takes 8 hours to travel the distance.
Concept Used:
Distance = Speed × Time
Calculation:
Car C speed is 20% less than Car B.
The speed of Car C = (100 - 20)/100 × 50 = 40 km/hr
Car B travels at speed of 50 km/hr.
The distance travels by Car C in 2 hours = 40 × 2 = 80km
The relative velocity of Car B and Car C = 50 - 40 = 10 km/hr
The time when Car B meets Car C = 80/10 = 8 hours
∴ Car B meets Car C after 8 hours.