Correct Answer - Option 2 : 10 hours
Given:
Car A travels some distance which \(33\frac{1}{3}\% \) more than the distance travelled by Car B.
Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.
Car C travels a distance of 400 km at 20% less speed than Car B.
The Car A takes 8 hours to travel the distance.
Concept Used:
Distance = Speed × Time
Calculation:
Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.
Car C speed is 20% less than Car B.
The speed of Car C = (100 - 20)/100 × 50 = 40 km/hr
Car C travels a distance of 400 km.
The time taken by Car C = 400/40 = 10 hours
∴ The time taken by Car C is 10 hours.