Correct Answer - Option 4 :
62.5 Km/hr
Given:
Car A travels some distance which \(33\frac{1}{3}\% \) more than the distance travelled by Car B.
Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.
Car C travels a distance of 400 km at 20% less speed than Car B.
The Car A takes 8 hours to travel the distance.
Concept Used:
Distance = Speed × Time
Calculation:
Car B travels at speed of 50 km/hr for \(7\frac{1}{2}\) hours.
The distance travels by Car B = 50 × \(7\frac{1}{2}\)
⇒ 50 × 15/2 = 25 × 15 = 375km
Car A travels some distance which \(33\frac{1}{3}\% \) more than the distance travelled by Car B.
The distance travels by Car A = (100 + \(33\frac{1}{3}\))/100 × 375 = 4/3 × 375 = 500
Car A takes 8 hours to travel the distance.
Then, the speed of Car A = 500/8 = 62.5 km/hr
∴ The speed of Car A is 62.5 km/hr.
