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If y is a negative number such that \({2^{{y^2}{{\log }_3}5}} = 5{ ^{lo{g_2}3}}\), then y equals
1. - log2(1/5)
2. log2(1/5)
3. -log2(1/3)
4. log2(1/3)

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Correct Answer - Option 3 : -log2(1/3)

Calculation:

\({2^{{y^2}{{\log }_3}5}} = 5{ ^{lo{g_2}3}}\)

ax = N

x = logaN

According to the properties

⇒ y2log35 = log25log23

⇒ y2log35 = log23 × log25 (by using logaMx = xlogaM)

⇒ y2 = (log23 × log25)/log35

⇒ y2 = {(loge3/loge2) × (loge5/loge2)/(loge​5/loge3)}

⇒ y2 = (loge3/loge2)2

⇒ y = (+ or –) loge3/loge2

If y is negative

⇒ y = – log2(1/3)

∴ The value of y is – log2(1/3).

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