Correct Answer - Option 3 : 2.05 m
Concept:
The specific energy may be given as
\(E = y + \frac{{V_1^2}}{{2g}}\)
Calculation:
We know that
Q = AV
⇒ 10 = 5 × 2 × V
⇒ V = 1 m/s
\(\begin{array}{l} E = y + \frac{{V_1^2}}{{2g}}\\ E= 2 + \frac{{{{\left( {1} \right)}^2}}}{{2 \times 9.81}} = 2.05\;m \end{array}\)