Correct Answer - Option 1 : 0.48 m
Concept:
The off-tracking on the road is given by:
\({E_{off}} = \frac{{{nl^2}}}{{2R}}\)
where
n = number of lanes
L = wheel-base
R = Radius of the curve
Eoff = Off-tracking
Calculations:
Pavement width is 2.5 m, So Number of lanes(n) = 1
\({E_{off}} = \frac{{{1\ \times
5.5^2}}}{{2 \times 31.5}} = 0.48\;m\)