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A simply supported beam of span 6 m carries an ultimate UDL of 25 kN/m. The plastic moment capacity of the same is
1. 146.85 kN-m
2. 112.5 kN-m
3. 102.5 kN-m
4. 125.45 kN-m

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Correct Answer - Option 2 : 112.5 kN-m

Concept:

Plastic moment capacity for the simply supported beam with UDL;

\({M_p} = \frac{{w{l^2}}}{8}\)

Calculation:

Given;

w = 25 KN/m

l= 6 m

From above equation:

\({M_p} = \frac{{25 \times {6^2}}}{8}\) = 112.5

Mp = 112.5 KN - m

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