Correct Answer - Option 1 : increase
CONCEPT:
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Heat is a form of energy that flows from a relatively warmer object to a relatively cooler object.
The rate of Heat transfer is given by:
\( {Δ Q \over Δ t} = {KAΔ T \over d}\)
where \( {Δ Q \over Δ t} \) is the rate of heat transfer, K is the thermal conductivity of the material, A is the cross-section area of the rod, ΔT is the difference in temperature at both ends of the rod, and d is the length of the rod.
EXPLANATION:
Given that:
Temperature Difference and length are constant.
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Thermal conductivity is the property of material so constant
The rate of heat transfer \( {Δ Q \over Δ t}\)
\( {Δ Q \over Δ t} = {KAΔ T \over d}\)
Since K, ΔT, d are cont.
So \( {Δ Q \over Δ t} \propto {A }\)
- Hence If the cross-sectional area of the rod is increased, the rate of heat conduction will also increase.
- So the correct answer is option 1.
