Correct Answer - Option 5 : 4YA
Given series:
Left side 2 # C D 6 % F I M K H 8 © @ T U V 4 € 2 7 8 $ H O K W 5 Y 4 ¥ Y A P @ Right side
According to the positions of the elements in the series:
1) C6F → C + 2 = 6 and 6 + 2 = F
2) H©T → H + 2 = © and © + 2 = T
3) 7$O → 7 + 2 = $ and $ + 2 = O
4) V€7 → V + 2 = € and € + 2 = 7
5) 4YA → 4 + 2 = Y and Y + 1 = A
Hence, 4YA does not belong to the group.