Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
70 views
in Physics by (114k points)
closed by
The momentum of a photon of energy 1 MeV in kg m/s, will be
1. 0.33 × 106
2. 7 × 10–24
3. 10–22
4. 5 × 10–22

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 4 : 5 × 10–22

CONCEPT:

  • The energy of an incident wavelength,λ, is given as 

\(\Rightarrow E = \frac{hc}{\lambda }\)

Substitute the value \(\lambda =\frac{h}{mV}\)in the above equation it becomes 

\(\Rightarrow E = \frac{hc}{\dfrac{h}{mV}} = C\ mV\)

\(\Rightarrow E = PC\)

  • The relation between energy and momentum is given by

⇒ E = PC

Where P = momentum and C = Velocity of light

CALCULATION : 

Given - E = 1MeV = 1 × 10× 1.69 × 10-19J, C = 3 × 108m/s

  • The momentum of the particle can be written as

\(\Rightarrow P = \dfrac{10^{6}\times 1.69\times 10^{-19}}{3\times 10^{8}} =5.63\times 10^{-22} Kgm/s\)

  • Hence, option4 is the answer

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...