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\(\sqrt {6 + \sqrt {6 + \sqrt {6 + \sqrt {6 + ...\infty } } } } \) = ?
1. 3
2. 2
3. 5
4. 6

1 Answer

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Best answer
Correct Answer - Option 1 : 3

Given:

\(\sqrt {6 + \sqrt {6 + \sqrt {6 + \sqrt {6 + ...\infty } } } } \)

Concept used:

Simplification

Calculation:

Here we have 6 inside

So take two numbers which are factors of 6

Let the two numbers be 2 and 3

Break them in the consecutive order.

⇒ 2 × 3 = 6

In the case of addition the larger number will be the answer.

∴ Ans : 3

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