Correct Answer - Option 4 : x + 4y - 11 = 0

**Concept:**

The equation of the line with points (x_{1}, y_{1}) and (x_{2}, y_{2})

\(\rm {y-y_1\over x - x_1} = {y_2 - y_1\over x_2 - x_1}\)

**Calculation:**

Given lines x - y + 4 = 0 ...(i)

y - 2x - 5 = 0 ...(ii)

Adding the 2 equation (i) and (ii)

-x - 1 = 0

x = -1

Putting it in equation (i)

-1 - y + 4 = 0

y = 3

Intersection of the lines (-1, 3)

Now the equation of the line to be find out is

\(\rm {y-3\over x -(-1)} = {2 - 3\over 3 - (-1)}\)

4(y - 3) = -1(x + 1)

**4y + x - 11 = 0**