Correct Answer - Option 3 : 28 years
Given∶
Tony’s age was 30 years older than his sister Sara.
Mother Marry was 20 years older than this brother Sam.
Sara is 4 years elder than Sam.
After 2 years, the average age of Tom’s family is 20.
Formula Used∶
Concept of Average, Linear Equations.
Calculation∶
Let the present age of Sam be ‘x’ years
Then, Sara’s age = (x + 4) years
Tony’s age = 30 + x + 4 = (x + 34) years
Marry’s age = (20 + x) years
So, the sum of their ages = x + x + 4 + x + 34 + 20 + x = 4x + 58
After 2 years, the sum of their ages will increased by 2 × 5 = 10 years
∴ The sum of their ages after 2 years = 4x + 58 + 10 = (4x + 68) years ----(1)
Also, The average age of 5 members of Tom’s family = 20
So, Sum of their ages = 20 × 5 = 100 (2)
On equating eq. (1) and (2), we get
4x + 68 = 100
⇒ 4x = 32
⇒ x = 8
Marry’s age = 20 + x = 20 + 8 = 28 years.
∴ When Tom was born, Marry’s age was of 28 years.